3.8x-0.01x^2=0

Solution for 3.8x-0.01x^2=0 equation:

3.8x-0.01x^2=0

a = -0.01; b = 3.8; c = 0;
Δ = b2-4ac
Δ = 3.82-4·(-0.01)·0
Δ = 14.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.8)-\sqrt{14.44}}{2*-0.01}=\frac{-3.8-\sqrt{14.44}}{-0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.8)+\sqrt{14.44}}{2*-0.01}=\frac{-3.8+\sqrt{14.44}}{-0.02}
$